Correct answer: 33088.40. H = nCPT= 5  4R  (1727.21 - 900) = 5  4  2  827.21 = 33088.40 Cal

See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardNUMERICAL

Question

See image

Answer: 33088.40

💡 Solution & Explanation

H = nCPT= 5  4R  (1727.21 - 900) = 5  4  2  827.21 = 33088.40 Cal

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry