What is the volume occupied by 2 mole of a perfect gas at 2 atm and 66.67°N? — States of Matter and Gaseous State Chemistry Question
Question
What is the volume occupied by 2 mole of a perfect gas at 2 atm and 66.67°N?
Answer: A
💡 Solution & Explanation
T = 66.67 + 233.33 = 300 K_N. Using PV = nRT with R = 0.12: V = nRT / P = 2 × 0.12 × 300 / 2 = 36 L.
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