The ratio of energies of first excited state of He^+ ion and ground state of H-atom is — Atomic Structure Chemistry Question

💡 Solution & Explanation

The energy of an electron in a Bohr orbit is E_n = -13.6 * Z^2 / n^2 eV. For the first excited state of He^+ (n = 2, Z = 2): E_He+ = -13.6 * 2^2 / 2^2 = -13.6 eV. For the ground state of H-atom (n = 1, Z = 1): E_H = -13.6 * 1^2 / 1^2 = -13.6 eV. The ratio of their energies is -13.6 eV / -13.6 eV = 1:1.