Br KOH alcoholic P Br Q 2-Bromopentane Major Product Consider the above sequence of reactions. 151 g — JEE Mains Chemistry Past Papers Chemistry Question
Question
Br KOH alcoholic P Br Q 2-Bromopentane Major Product Consider the above sequence of reactions. 151 g of 2-bromopentane is made to react. Yield of major product P is 80% whereas Q is 100%. Mass of product Q obtained is _________g. (Given molar mass in g mol–1 H : 1, C : 12, O : 16, Br : 80)
Answer: .
💡 Solution & Explanation
Br KOH . Alc (P) Br Br Br Molar mass of 2-Bromopentane is 151 so moles of 2-Bromopentane will be 1.0 Moles of 'P' = 1.0 × 0.8 = 0.8 moles of Q = 0.8 mass of product Q = 0.8 × 230 = 184 Molar mass of Q is 230.
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