PbSiF6 + H2SiF6 + gelatine is taken as electrolyte in electrolytic refining of lead. β Metallurgy and Isolation of Elements Chemistry Question
Question
PbSiF6 + H2SiF6 + gelatine is taken as electrolyte in electrolytic refining of lead.
Answer: C
π‘ Solution & Explanation
Step 1: Highly electropositive metals (like alkali and alkaline earth metals) have a very high affinity for oxygen and carbon. Step 2: At the high temperatures required for carbon reduction, these metals readily react with the reducing agent (carbon) to form very stable ionic metal carbides rather than the free metal. Step 3: Consequently, carbon reduction is not a commercially viable method for extracting highly electropositive metals. Thus, the correct option is (b).
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