Correct answer: 108.   º eq 3 4 2 Ba PO 160 140 100         = 200 Ohm–1 cm2 eq–1 Now,         5 º eq eq

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 108

💡 Solution & Explanation

  º eq 3 4 2 Ba PO 160 140 100         = 200 Ohm–1 cm2 eq–1 Now,         5 º eq eq

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