Consider the following complex compounds :
(i) [Pt(NH3)2(SCN)2]
(ii) [Co(NH3)3(NO2)3]
(iii) [Pt(en)Cl2]
(iv) [Cr(en)2Br2]+
(v) [Rh(en)3]3+
(vi) [CoCl2Br2]2-
Then calculate sum of

Question

Consider the following complex compounds :
(i) [Pt(NH3)2(SCN)2]
(ii) [Co(NH3)3(NO2)3]
(iii) [Pt(en)Cl2]
(iv) [Cr(en)2Br2]+
(v) [Rh(en)3]3+
(vi) [CoCl2Br2]2-
Then calculate sum of total number of geometrical isomers in all above complex compounds.

Prashant Kotian · Accepted Answer

Correct answer: **ANSWER: 6**<BR>SOLUTION: NUMBER OF GEOMETRICAL ISOMERS FOR EACH: (I) 2, (II) 2, (III) 0, (IV) 2, (V) 0, (VI) 0. SUM = 6.. Step 1: Co(CO)4 has an EAN of 35, which is one electron short of the stable noble gas configuration (Krypton, EAN = 36). Step 2: It can achieve an EAN of 36 either by gaining one electron via reduction to form [Co(CO)4]^- or by sharing an electron via dimerisation to form Co2(CO)8 with a Co-Co metal-metal bond. Step 3: Since both reduction and dimerisation allow the cobalt atom to attain a stable EAN of 36, the correct option is (d).

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