See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

[1.33 – 1.34] Sol. Number of triangular faces in truncated cube = 8 Number of octagonal faces in truncated cube = 6 Each corner of the cube will become a triangular face and each square face will become an octahedral face in a truncated solid cube. For More Material Join: @JEEAdvanced_2025 AITS-OT-II (Paper-1)-PCM(Sol.)-JEE(Advanced)/2025 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 14 Mathematics PART – III Section – A