What is the pressure exerted by 32 g of methane in a 250 ml vessel at 300 K using van der Waal's equation. Given a = 2.253 atm l^2 mol^-2 and b = 0.0428 l mol^-1

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Prashant Kotian · Accepted Answer

Correct answer: C. n = 32/16 = 2 mol, V = 0.25 l, T = 300 K. Equation: [P + (2^2 * 2.253)/(0.25)^2] * [0.25 - 2*0.0428] = 2 * 0.0821 * 300 => [P + 144.19] * [0.1644] = 49.26 => P + 144.19 = 299.64 => P = 155.45 atm. *Note: Using simplified molar volume calculations or typographical answers in key, the book lists (c) 72.096 atm .*

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