See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

  Y y m X x    Put X 0  Y y mx   2 y mx x    dy 1 y x dx x  (linea r DE) Solving 2 y x cx   x 1,y 1    c 2  2 y 2x x   1 0 1 2 (0, y– mx) (x, y)