See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Sol. Heat energy flowing per sec is given by Q H KA t x     . . . (i) if dm mass of ice is increased in time dt, then dm A dx dx A. . dt dt dt     Since, dm H L dt        dx H A L dt   . . . (ii) From eq. (I) and (II) dx A L KA dt x     Rate of thickening of ice = dx/dt  dx KA dt AL x    = K L x   = 4 3 2 4 10 0 ( 15)