See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

MO configurations 2 2 2 2 2 2 x y z N KK 2s * 2s 2p 2p 2p       2 2 2 2 2 2 2 2 z x y x y F KK 2s * 2s 2p 2p 2p * 2p * 2p         2 2 O same as F  2 2 2 2 2 x y C KK 2s * 2s 2p 2p     