Consider the following reaction Propanal + Methanal O H ) iv ( NaCN ) iii ( ) ii ( NaOH . di )i( ) O — JEE Mains Chemistry Past Papers Chemistry Question
Question
Consider the following reaction Propanal + Methanal O H ) iv ( NaCN ) iii ( ) ii ( NaOH . di )i( ) O H C ( 8 B Product The correct statement for product B is. It is (A) optically active and adds one mole of bromine (B) optically active alcohol and is neutral (C) racemic mixture and gives a gas with saturated NaHCO3 solution (D) racemic mixture and is neutral
Answer: C
💡 Solution & Explanation
CH3CH2–C–H O Propanal CH2=C–C–H O CH3 NaCN CH2=C–CH–CN OH CH3 * (R/S) H3O+ CH2=C–CH–COOH OH CH3 * (R/S) (B) dil. NaOH, aldol condensation H–C–H + O Methanal
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