See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

   eq K 3 2 O g O g O g            2 3 eq eq 3 2 O O O K O K O O    Rate determining step    k 2 3 NO g O g NO g           3 2 2 eq 2 O rate k NO O k NO K O       1 eq 2 3 2 k K NO O O       1 2 3 2 k NO O O      eq k K .k  Overall order = 1 + 1 – 1 = 1.