See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Since the line y mx 1   touches 4 2 y x 2x x,    Curve 4 2 x 2x x mx 1      should have coincident solution. i.e. 1 1 x ,x and 2 2 x ,x      2 2 4 2 1 2 x 2x m 1 x 1 x x x x        On comparing, we get 1 2 x 1, x 1   1 2 y 2; y 0     2 2 1 1 2 2 2 2 x y 1 4 5 1 0 x y      