K2[Cd(CN)4] + H2S -> CdS↓ + 2KCN + 2HCN — Redox Reactions and Volumetric Analysis Chemistry Question
Question
K2[Cd(CN)4] + H2S -> CdS↓ + 2KCN + 2HCN
Answer: A
💡 Solution & Explanation
Step 1: Potassium tetracyanocadmate(II), K2[Cd(CN)4], is a soluble complex in water. Step 2: Passing H2S gas through this solution decomposes the relatively less stable cadmium complex to precipitate highly insoluble yellow cadmium sulfide, CdS↓. Step 3: Since a solid precipitate forms from a soluble starting material, this is a precipitate formation reaction (type A), corresponding to option (a).
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