See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 2 3 2 2 4 6 2Na S O I Na S O 2NaI    n-factor of I2 = 2 Therefore, number of m moles of I2 = M 15 15 40 40   Number of m moles of 2 2 3 15 15 Na S O 2 40 20    in 10 mL solution. Weight of   2 2 3 2 Na S O .5H O in g in 10 mL solution 3 15 10 248