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The resistance of conductivity cell with cell constant 1.14 cm–1, containing 0.001 M KCl at 298 K is — JEE Mains Chemistry Past Papers Chemistry Question

Question

The resistance of conductivity cell with cell constant 1.14 cm–1, containing 0.001 M KCl at 298 K is 1500. The molar conductivity of 0.001 M KCl

Answer: .

💡 Solution & Explanation

K = – cm S . 1500 A R                 . 1500 . 1000 m          S cm2 mol–1 = 760 S cm2 mol–1  760

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