The work done in the isothermal reversible expansion of argon gas at 27°C from 4 l to 16 l was equal to 4200 cal. What is the amount of argon subjected to such an expansion? (Ar = 40, ln4 = 1.4)

Question

Prashant Kotian · Accepted Answer

Correct answer: C. W = nRT ln(V2/V1) => 4200 = n * 2 * 300 * ln(16/4) => 4200 = n * 600 * ln(4) => 4200 = n * 600 * 1.4 => 4200 = 840 * n => n = 5 moles. Mass of argon = n * Molar Mass = 5 * 40 = 200.0 g.

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