45 . – 70 . 3 . 2 Fe Fe Fe FeO V V V 2 4 /Fe FeO E is x × 10–3 V. The value of x is _______ — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

– 4 FeO + 8H+ + 3e–  Fe3+ + 4H2O 1 E = 2.20 V 1 G  = –3F(2.20) Fe3+ + e–  Fe2+ 2 E = 0.7 V 2 G  = –1 × F(0.7) _________________________________________________________ Target eq. – 4 FeO + 8H+ + 4e–  Fe2+ + 4H2O 3 E = ? 3 G  = –4 × F( 3 E ) Target eq. = eq1 + eq2 –4F 3 E = –3F × 2.20 – 1 × F (0.7) 3 E =       7 . 20 . 3 = 1.825 = 1825 × 10–3 V | JEE(Main) 2023 | DATE : 10-04-2023 (SHIFT-1) | PAPER-1 | OFFICIAL PAPER | CHEMISTRY PAGE # 10