See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Total moles 2 2 2 6     5 3 2 2 3/ 6 1, 1, 1 PCl PCl PCl p p p       1 1 1 1 p K atm   When volume is double (i.e. 2 V V  ) at constant P and T, total moles become = 12. If volume is doubled, reaction will more backward at constant P and T.     5 3 2 2 3, 3 12 12 PCl PCl y y p p         2 2 3 12 Cl x y p     AITS-CRT-II (Paper-1)-PCM(Sol.)-JEE (Advanced)/2021 Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 5    2 2 3 3 12 12 1 ..... 1 2 3 12 p x y y K y                          Also   2 2 2 12 y y x y        From equations (i) and (ii), solve y = 2/3, x = 20/3