Match List I with List II List I Complex List II Crystal Field Splitting energy (0) A. [Ti(H2O)6]2+ I. – 1.2 B. [V(H2O)6]2+ II. – 0.6 C. [Mn(H2O)6]3+ III. 0 D. [Fe(H2O)6]3+ IV. – 0.8 Choose the correc

Question

Match List I with List II List I Complex List II Crystal Field Splitting energy (0) A. [Ti(H2O)6]2+ I. – 1.2 B. [V(H2O)6]2+ II. – 0.6 C. [Mn(H2O)6]3+ III. 0 D. [Fe(H2O)6]3+ IV. – 0.8 Choose the correct answer from the options given below:

(A) A-II, B-IV, C-III, D-I
(B) A-IV, B-I, C-II, D-III
(C) A-II, B-IV, C-I, D-III
(D) A-IV, B-I, C-III, D-II

Prashant Kotian · Accepted Answer

Correct answer: B. [Ti(H2O)6]2+ ON of Ti = +2 Ti+2 = 3d2 ( ,1,1 g 2t , , g e ) C.F.S.E = - 0.8 o [V(H2O)6]2+ ON of V = +2 V+2 = 3d3 ( 1,1,1 g 2t , , g e ) C.F.S.E = - 1.2 o [Mn(H2O)6]3+ ON of Mn = +3 Mn+3 = 3d4 (W.F.L) 1,1,1 g 2t , , g e C.F.S.E = (- 1.2 + 0.6) o = - 0.6 o [Fe(H2O)6]3+ ON of Fe = +3 (W.F.L)  3d5 1,1,1 g 2t , 1,1 g e C.F.S.E = 0 JEE (Main) 2023 | DATE: 10-04-2023 (SHIFT-2) | OFFICIAL PAPER | PAPER-1 | CHEMISTRY PAGE # 4

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