The specific heats of iodine vapours and solid are 0.031 and 0.055 cal/g, respectively. If the enthalpy of sublimation of iodine is 24 cal/g at 200°C, then the enthalpy of sublimation of iodine at 250

Question

The specific heats of iodine vapours and solid are 0.031 and 0.055 cal/g, respectively. If the enthalpy of sublimation of iodine is 24 cal/g at 200°C, then the enthalpy of sublimation of iodine at 250°C should be

Prashant Kotian · Accepted Answer

Correct answer: B. δ = (g) - (s) = 0.031 - 0.055 = -0.024 cal/(g °C). Using Kirchhoff's equation: δ H(250°C) = 24 + (-0.024) * (250 - 200) = 24 - 1.2 = 22.8 cal/g.

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