The standard reduction potentials at 298 K for the following half cells are given below : Cr2O7 2– + 14H+ + 6e– 2Cr3+ + 7H2O, E° = 1.33V Fe3+ (aq) + 3e– Fe E° = –0.04V Ni2+ (aq) + 2e– Ni E° = –0.25V A

Question

The standard reduction potentials at 298 K for the following half cells are given below : Cr2O7 2– + 14H+ + 6e– 2Cr3+ + 7H2O, E° = 1.33V Fe3+ (aq) + 3e– Fe E° = –0.04V Ni2+ (aq) + 2e– Ni E° = –0.25V Ag+ (aq) + e– Ag E° = 0.80V Au3+ (aq) + 3e– Au E° = 1.40V Consider the given electrochemical reactions, The number of metal(s) which will be oxidized be Cr2O7 2–, in aqueous

Prashant Kotian · Accepted Answer

Correct answer: .. Fe, Ni, Ag will be oxidized due to lower S.R.P.

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