The work functions of two metals (MA and MB) are in the 1 : 2 ratio. When these metals are exposed to photons of energy 6 eV, the kinetic energy of liberated electrons of MA : MB is in the ratio of 2.

Question

The work functions of two metals (MA and MB) are in the 1 : 2 ratio. When these metals are exposed to photons of energy 6 eV, the kinetic energy of liberated electrons of MA : MB is in the ratio of 2.642 : 1. The work functions (in eV) of MA and MB are respectively.

(A) 3.1, 6.2
(B) 2.3, 4.6
(C) 1.4, 2.8
(D) 1.5, 3.0

Prashant Kotian · Accepted Answer

Correct answer: B. KEmax = E –  (KEmax)1 = 6 – 1 ...... (1) (KEmax)2 = 6 – 2 ...... (2) By eq. (1) divide eq. (2) max 1 max 2 (KE ) 2.642 (KE ) 6     1 2.642 6    1 = 2.3 eV 2 = 4.6 eV. ALLEN 

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