Correct answer: 4. 235 1 140 92 1 92 0 54 38 0 U n Xe Sr 4 n    

See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardNUMERICAL

Question

See image

Answer: 4

💡 Solution & Explanation

235 1 140 92 1 92 0 54 38 0 U n Xe Sr 4 n    

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry