Consider the following reactions :<br>(i) PCl3 + 3H2O H3PO3 + 3HCl<br>(ii) SF4 + 3H2O H2SO3 + 4HF<br β p Block Elements Chemistry Question
Question
Consider the following reactions :<br>(i) PCl3 + 3H2O $\rightarrow$ H3PO3 + 3HCl<br>(ii) SF4 + 3H2O $\rightarrow$ H2SO3 + 4HF<br>(iii) BCl3 + 3H2O $\rightarrow$ H3BO3 + 3HCl<br>(iv) XeF6 + 3H2O $\rightarrow$ XeO3 + 6HF<br>Then according to given information the incorrect statement is :
π‘ Solution & Explanation
Step 1: Xenon forms stable compounds primarily with highly electronegative and small atoms like fluorine and oxygen, which can effectively oxidize xenon to positive oxidation states. Step 2: Chlorine is larger and less electronegative than oxygen and fluorine, and is unable to stabilize the higher oxidation states of xenon under normal conditions. As a result, XeCl4 does not exist. Step 3: Therefore, XeCl4 is the compound that cannot be formed by xenon, corresponding to option (c).