See image | AITS & Test Series — Chem-Mantra

Name: JEE Advanced Chemistry
Price: 7999 INR
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Question

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Answer: 2

💡 Solution & Explanation

W = -PV = -P(V2 – V1) 2 1 nRT nRT P P P         = -nR(T2 – T1) = -1  8(400 - 150) = -2000 J = -2 KJ mol–1 = -x  x = 2 SECTION – C

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