See image — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Step 1 - Identify the functional group: The molecule contains an ester linkage (-C(=O)-O-), so it is an ester and must be named as [alcohol-derived part] [acid-derived part]ate. Step 2 - Identify the alcohol-derived (alkoxy) portion: The oxygen on the right side of the carbonyl is connected to -CH2-CH=CH2, which is the allyl group, systematically named prop-2-en-1-yl. This gives the prefix 'prop-2-enyl'. Step 3 - Identify the acid-derived portion: The carbonyl carbon is connected to -CH2-CH(CH2CH3)-CH=CH2. Counting from the carbonyl carbon: C1 (carbonyl C), C2 (CH2), C3 (CH bearing the ethyl branch), C4 (CH=), C5 (=CH2). This is a five-carbon chain with a terminal double bond at C4-C5, making it pent-4-enoic acid. There is an ethyl substituent at C3. Step 4 - Assemble the IUPAC name: Alcohol part = prop-2-enyl; Acid part = 3-ethylpent-4-enoate. Combined: prop-2-enyl 3-ethylpent-4-enoate. Step 5 - Verify numbering: The carbonyl carbon is C1 of the acid chain; the double bond in the acid chain starts at C4 (pent-4-enoate); the ethyl group is at C3. The ester oxygen bears the prop-2-en-1-yl group. All consistent. Therefore, the correct answer is prop-2-enyl 3-ethylpent-4-enoate.