Correct answer: 00000.50. 2 A 1 T mv 2  h mv  2 2 1 m v 2 m  2 2 B 1 h 2 m   … (1) 2 B 2 A 1 h T 2 m   … (2) 2 A B 2 B A T 4 T      Again B A T T

See image | AITS & Test Series — Chem-Mantra

Question

See image

Answer: 00000.50

💡 Solution & Explanation

2 A 1 T mv 2  h mv  2 2 1 m v 2 m  2 2 B 1 h 2 m   … (1) 2 B 2 A 1 h T 2 m   … (2) 2 A B 2 B A T 4 T      Again B A T T

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

Ask on WhatsApp →

💡 Solution & Explanation

Practice 22,000+ questions like this