See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Equation of tangents & PA PB is   2 2 2 4 9 2 1 4 9 y mx m m m       AITS-CRT-IV (Paper-1)-PCM(Sol.)-JEE(Advanced)/20 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 10   5 4 10 2 5 1 2 2 2 2 5 10 5 2 8 m m y x y x x y               Equation of AB 18 4 36 x y   9 2 18 x y    x Coordinate of B 5 4 10, 2 x x  