See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let we assume one corner of unit cell at origin so the corners of units cell will be at A (0, 0, 0) B (8 3 , 0, 0), C( 8 3 , 0, 8 3 ), D (0, 0, 8 3 ), w (0, 8 3 , 8 3 ), x (8 3 , 8 3 , 8 3 ), y(8 3 , 8 3 , 0), z (0, 8 3 , 0), Now two nearest octahedral void which will be either on edge centre of body centre will be nearest to tetrahedral void on nearest body diagonal. So, tenth of body diagonal =  8 3 3 24Å  , Let octahedral void is on AD and nearest tetrahedral void is on AX from ¼ of total AX from A So, coordinate of octahedral centre = (0, 0, 4 3 ) Coordinate of tetrahedral centre =   2 3,2 3,2 3 Distance b/w these voids =       2 2 2 2 3 2 3 2 3   = 6Å SECTION – C