At moderate pressure, the compressibility factor for a gas is given as: Z = 1 + 0.35P - 168/T P, whe — States of Matter and Gaseous State Chemistry Question
Question
At moderate pressure, the compressibility factor for a gas is given as: Z = 1 + 0.35P - 168/T P, where P is in bar and T is in Kelvin. What is the Boyle's temperature of the gas?
Answer: B
💡 Solution & Explanation
at boyle's temperature (t_b), z = 1 because the gas behaves ideally. thus, the coefficient of p must be zero: 0.35 - 168 / t_b = 0 → t_b = 168 / 0.35 = 480 k.
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