For a reaction 2 -> + 3, it is observed that -d[]/dt = K1[]; +d[]/dt = K2[] and +d[]/dt = K3[]. The β Chemical Kinetics Chemistry Question
Question
For a reaction 2$NH_3$ -> $N_2$ + 3$H_2$, it is observed that -d[$NH_3$]/dt = K1[$NH_3$]; +d[$N_2$]/dt = K2[$NH_3$] and +d[$H_2$]/dt = K3[$NH_3$]. The correct relation between K1, K2 and K3 is
Answer: C
π‘ Solution & Explanation
Rate of reaction = -1/2 d[$NH_3$]/dt = +d[$N_2$]/dt = +1/3 d[$H_2$]/dt. Substituting the given rate expressions: 1/2 K1 [$NH_3$] = K2 [$NH_3$] = 1/3 K3 [$NH_3$] => 1/2 K1 = K2 = 1/3 K3. Multiplying the entire relation by 6 gives: 3K1 = 6K2 = 2K3.
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