See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Radius (x1) of nth orbit for H-atom = r1 × n2 If n is lower orbit, the next orbit = n + 1 and x2 = r1 (n + 1)2 = r1(n2 + 2n + 1) x2 – x1 = r1 (2n + 1) If n is higher orbit, then consecutive lower orbit = n – 1 and     2 2 2 1 1 x r n 1 r n 2n 1          2 2 1 2 1 1 1 x x r n r n 2n 1 r 2n 1          