See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

O O O OH O O + O H * (A) (B) Retention in configuration in both (A) and (B) OH O O * H3O + O + CO2 In (C) and (D) no chiral carbon present. O Br2/ h Br O Br O O Br + + (C) (D) (E) * * (C)  Chiral carbon only in the 1st compound formed from (C). This will exist in the enantiomeric pair.  Sum of total number of optically active products = 4. But total number of enantiomeric pairs = 1