See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

AgNO3 + HCl  AgCl + HNO3 o m AgCl = 4 4 4 2 1 (133 10 426 10 421 10 )Sm mol          = 4 2 1 (138 10 )Sm mol    For AgCl m = o m  m AgCl(pure) =( 4 10 68 .2   - 4 10 86 .0   ) Sm–1 = 4 10 82 .1   Sm–1 m 1000 C    , here C =solubility Ksp (AgCl) = C2