The number of neutrons present in the more abundant isotope of boron is 'x'. Amorphous boron upon he — JEE Mains Chemistry Past Papers Chemistry Question
Question
The number of neutrons present in the more abundant isotope of boron is 'x'. Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is 'y'. The value of x + y is … (A) 4 (B) 6 (C) 3 (D) 9
Answer: D
💡 Solution & Explanation
More abundant isotope = B11 [Number of neutrons = 6] x = 6 B + O2 B2O3 Oxidation state of B in B2O3 = +3 So, y = 3 Hence x + y = 9 SECTION-B
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