Statement I: is more likely to show Schottky defect while LiI is more likely to show Frenkel defect. β Solid State Chemistry Question
Question
Statement I: $KCl$ is more likely to show Schottky defect while LiI is more likely to show Frenkel defect. Statement II: Schottky defect is more likely in ionic solids in which cations and anions are of comparable size while Frenkel defect is more likely in ionic solids in which cations and anions have large differences in their ionic sizes.

Answer: A
π‘ Solution & Explanation
Statement I is correct: in $KCl$, K+ and Cl- are of similar size, favoring Schottky defects; in LiI, the Li+ cation is very small compared to the I- anion, favoring Frenkel defects. Statement II is correct and is the exact explanation of Statement I.
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