What will be the final pressure (≈)? — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

P1V = n1RT1, P2V = n2RT2 → P2 = P1 × (n2/n1) × (T2/T1).<br>Initial moles n1 = 1 mol $H_2$ + 0.5 mol $O_2$ + 2 mol $N_2$ = 3.5 mol.<br>Final moles n2 = 1 mol $H_2O$ + 2 mol $N_2$ = 3.0 mol.<br>P2 = 1.0 atm × (3.0 / 3.5) × (2940 / 298) = 0.857 × 9.866 = 8.46 atm ≈ 8.5 atm.