Correct answer: B. For 50% ionization(In–) = [HIn]  pH = PKIn Thus PKIn= 10–5 (as pH = 5)

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AITS & Test SerieshardMCQ SINGLE

Question

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Answer: B

💡 Solution & Explanation

For 50% ionization(In–) = [HIn]  pH = PKIn Thus PKIn= 10–5 (as pH = 5)

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