Butane reacts with oxygen to produce carbon dioxide and water following the equation given below : C4H10(g) + 13 O2(g) 4CO2(g) + 5H2O(J) If 174.0 kg of butane is mixed with 320.0 kg of O2, the volume

Question

Butane reacts with oxygen to produce carbon dioxide and water following the equation given below : C4H10(g) + 13 O2(g) 4CO2(g) + 5H2O(J) If 174.0 kg of butane is mixed with 320.0 kg of O2, the volume of water formed in liters is ________. (Nearest integer) [Given: (a) Molar mass of C, H, O are 12, 1, 16 g mol–1 respectively, (b) Density of water = 1 g mL–1]

Prashant Kotian · Accepted Answer

Correct answer: .. C4H10 + O 13  4CO3 + 5H2O 3 × 103 10 × 103 moles of H2O formed = O H2 n = 5 × 2 × 10 × 103 Then O H2 w = 13  = 1.3846 × 105 g volume of H2O will be = 138.46 litre

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