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Boron trichloride on heating with ammonium chloride at 140C gives a compound (A) which on reductionAITS & Test Series Chemistry Question

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Boron trichloride on heating with ammonium chloride at 140C gives a compound (A) which on reduction with sodium borohydride followed by hydrolysis gives another compound (B) . Hence compound (A) and (B) are respectively. (A) inorganic graphite & ammonia (B) inorganic benzene & orthoboric acid (C) trichloroborazine & orthoboric acid (D) diborane & orthoboric acid

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