See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 5 2 2 2N O 4NO O t 0 10 0 0 t 6 8 2    [N2O5] left = 6 M. Rate of reaction = 2 × 10-5 × 6 = 12 × 10 – 5 M sec-1 Rate of formation of NO2 = 4 × 12 × 10-5 = 4.8 × 10 – 4 M sec-1