Which of the following has been arranged in order of decreasing bond dissociation energy: — p Block Elements Chemistry Question

💡 Solution & Explanation

Step 1: Bond dissociation energy (BDE) is inversely proportional to the bond length between two atoms of similar periods. Step 2: Across the third period, atomic size decreases from Phosphorus (P) to Sulfur (S) to Chlorine (Cl). Consequently, the bond lengths of their respective bonds with oxygen increase in the order: Cl-O < S-O < P-O. Step 3: Since shorter bonds are stronger and require more energy to break, the bond dissociation energy decreases in the order: Cl-O > S-O > P-O, which corresponds to option (d).