Pb(NO3)2 + 2KI -> PbI2↓ + 2KNO3 — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Step 1: Identify starting materials: Lead(II) nitrate (Pb(NO3)2) and potassium iodide (KI) are both highly soluble salts. Step 2: Analyze the reaction: Mixing these solutions leads to a double displacement reaction where lead(II) ions and iodide ions combine to form a brilliant yellow precipitate of lead(II) iodide (PbI2↓). Step 3: Since a solid precipitate forms from soluble reactants, this is a precipitate formation reaction (type A).