A bulb emits light of wavelength 1987.8/7 nm. The bulb is rated as 200 W and 14% of the energy is emitted as light. How many photons are emitted by the bulb per second?

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Question

Prashant Kotian · Accepted Answer

Correct answer: D. Power of light = 0.14 × 200 = 28 W. E per photon = hc/λ = 7 × 10^-19 J. N = 28 / (7 × 10^-19) = 4 × 10^19 photons/sec.

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