The energy of first (lowest) Balmer line of H atom is x J. The energy (in J) of second Balmer line o — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

Transition of first Balmer line n1 = 2; n2 = 3 E = x = 13.6 (1) 2 1 2        ….. (i) Transition of 2 nd Balmer line n1 = 2; n2 = 4 E = 13.6 (1) 2 1 2        ….. (ii) Divide Eq. (ii) by eq. (i) ALLEN  1 E 16 1 x 9     E 5 x   E x   E = 1.35x.