See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 H 2 2 1 1 1 R .Z 2 5          2 H 9 1 25 4 R .Z 25 4 108.5 10           2 10 H 1 1 25 4 Z . R 21 1085 10     916 25 4 1085 21     B. E. 2 2 Z