See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

2 2 2 2 H O K O H O 2KOH n 0        2 2 2 2 2 2 2 2 mol 2 mol H O K O 2H O 2KOH H O n 2         2 2 2 2 2 2 2 2 mol 1 mol H O 2KO 2H O 2KOH H O 1O n 1      Total = 0 + 2 + 1 = 3 mol of H2O2 Yashpatil TG~ @bohring_bot For More Material Join: @JEEAdvanced_2024 Rankers Academy JEE AITS-PT-I-PCM(Sol.)-JEE(Main)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 18 Mathematics PART – C SECTION – A